The offical NSC Puzzle Donkey Thread

[Lammy]

ehh? I thought you had to take the letter off the end of the name?

 

[Lammy]

How the hell do you get decimal places with + and - 1? He must be dividing at some point!

 

[Old Goat]

you do but have to put it back on the front of the word

Heifer or vixen?

 

[Lammy]

OK for the large number I have 64

(1+1) to the power of (1+1) ttpo (1+1+1)

for the smallest number I have

1 / (1+1) ttpo (1+1+1+1)

= 0.0625

 

[Schrödinger's Toad]

I can't think of the answer to 10 at all ...

 

[Kylies Stunt Arse]

OK for the large number I have 64

(1+1) to the power of (1+1) ttpo (1+1+1)

for the smallest number I have

1 / (1+1) ttpo (1+1+1+1)

= 0.0625

64 is wrong. but you're on the right lines!

 

[Lammy]

It's bigger than 64?

 

[Kylies Stunt Arse]

Yep, much bigger

 

[Lammy]

is 0.0625 right?

I hinestly can't see a way of getting bigger than 64??

 

[Old Goat]

I got 81 and 0.03704 but its not right yet...

 

[Lammy]

I got 81 and 0.03704 but its not right yet...

how?

 

[Kylies Stunt Arse]

This is the help I got from someone nice on their forum.


Basically using the 1's you can add them up to make 3 useful numbers [2, 2, 3].

Those additions need to be in brackets so 3 = (1+1+1)

Using only 2 of those numbers, the highest value you can get is 3^2 = 9 (where the ^ is done by placing the other numbers higher to represent a power)

That means the highest number is 2^(3^2) which is 512.

Written out fully that is (1+1)^((1+1+1)^{1+1}). Although if you write it out on paper then you don't need one of the sets of brackets (marked as {}) because that woudl be implicit (although mathematically incorrect). That is important to know for the smallest number which uses the same logic.

 

[Old Goat]

(1+1+1)^(1+1+1+1) = 81

and

1/(1+1+1)^(1+1+1) = 0.03704 to 5 decimal points

but 0.03704 x 81 = 3 or 3.00024 but neither of these works

 

[Schrödinger's Toad]

10? Help me here!

 

[Old Goat]

This is the help I got from someone nice on their forum.


Basically using the 1's you can add them up to make 3 useful numbers [2, 2, 3].

Those additions need to be in brackets so 3 = (1+1+1)

Using only 2 of those numbers, the highest value you can get is 3^2 = 9 (where the ^ is done by placing the other numbers higher to represent a power)

That means the highest number is 2^(3^2) which is 512.

Written out fully that is (1+1)^((1+1+1)^{1+1}). Although if you write it out on paper then you don't need one of the sets of brackets (marked as {}) because that woudl be implicit (although mathematically incorrect). That is important to know for the smallest number which uses the same logic.

no that is bollocks - if you get rid of the curly brackets it equals 16 and you cant leave them in as we only have 7 brackets to play with. If that is the right answer ....

 

[Kylies Stunt Arse]

10? Help me here!

Heifer or vixen?

 

[Kylies Stunt Arse]

no that is bollocks - if you get rid of the curly brackets it equals 16 and you cant leave them in as we only have 7 brackets to play with. If that is the right answer ....

It's the answer. Seriously. If you use that logic to get your smallest number, and I suggest that you start with -1 then the answer that gives you is correct.

 

[Lammy]

In that case the smallest number you can get is;

1/(2^(2^2))

2^2 = 4

2^4 = 16

1 / 16 = 0.0625

which it isn't because 3^3 is 27.

1 / 27 = 0.03704

 

[Hampden Park]

help with 4.2.2 name the flower
havnt got a clue
pm me please some1

 

[Schrödinger's Toad]

Not so much a flower, but the lovely wanderer is Venus.

Still can't get 4.2.10 - Heifer or Vixen?