even if two of the times had been say 25.6 and 27.1 you could still use the "26" factor, ie the first one would be -0.4 and the 2nd +1.1 when working out the average to add to the 26 at the end
Deduct 26secs from every trial, e.g. 1st one is 26.3 - 26 = 0.3
Add up the total of what's left and divide by number of swims for each swimmer,
Ave for Lizzie is 2.0/5 = 0.4 + 26 = 26.4
Ave for megan is 3.0/6 = 0.5 + 26 = 26.5
So Lizzie has faster average time, but
Megan had the fastest swim...