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Do you realise what this means? This means I'm a f***ing idiot and owe DTES an apology. Shit way to start the weekend.

That's been half my problem.

Ah yes, fair point. I was trying to use your method for a smaller simpler example so I could make sense of it, but ran out of balls :D That's the same method I used, as you're using the number of balls that are not drawn, ie, the 43 losing balls. So I understand/agree with all that. It would...

Actually the odds of winning one draw with 2 differing tickets are almost identical to the odds of winning one of 2 draws with 1 ticket for each.

Although that wasn't the point of your first post, what exactly did you mean by this ‘Correct. There are 13,983,816/20 = roughly 700,000.’ Yes, I fully understand that, but that’s not how to work out the odds of getting those two tickets. There’s no need to list them, we fully agree that...

Surely the odds of you not winning with the first ticket are (a) 13,983,815/13,983,816 (= 0.99999992848876) and the odds of you not winning with the second ticket (assuming the ticket is random, and could even be the same as the first) is the same, so the odds of you winning neither time are (a)...

I know what your point is, but I’m trying to explain that your workings are wrong. You’re saying that there are roughly 700,000 (699191) ways of getting 3 numbers in the first ticket, so the odds of a person buying 1 ticket and getting 3 numbers is 1 in 20, purely because there are 20 ways of...

Ignoring the losing numbers for a second (which we can't do, but we'll come to that) there are as you say, 20 ways of picking 3 out of 6 to satisfy (a) (in my workings, combination 6,3). There aren't however 20 ways of satisfying (b), because you've already used 3 of the winning numbers for (a)...

I haven't worked out the odds for you buying 3 tickets, but I have worked it out for you just buying 2: The total number of combinations, or the odds of getting all 6 numbers = combination (49,6) type COMBIN(49,6) into excel = 13,983,816 The odds of getting any 3 of those numbers is...

First half right, but second much more unlikely, as he didn't just get 3 numbers, he got the specific 3 that he missed the first time. I don't know how to work it out :(