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  1. wealdgull

    [Misc] Probability problem

    The way I've always thought about it is: - you pick one door. The chance of having picked the door with the prize behind it is 1/3. - you now have two choices: either open the door you picked, or open both of the doors you didn't. It should be obvious that it makes more sense to open both...
  2. wealdgull

    [Misc] Probability problem

    Not correct with the 50% bit. If there are 3 doors then you have a 1/3 chance of winning if you stick to your original choice and a 2/3 chance of winning if you switch your choice.
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