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..thinking along right lines....

thats one way (and the best answer imo), although with three balls he can hit a four and then the three with one short the next ball. There's another way too

only 3 balls left, so no break in overs

:clap2:my turn I guess Two batsman each on 94 runs. Seven runs needed to win in last 3 balls. Both make 100*. How?

County championship he can get 12 wickets a match for 16 matches, so 192 wickets (except he'd be called up for England with these stats) 50 over competition he can play 11 games so bowl 660 balls maximum, therefore to get a strikerate of 43 he gets 15 wickets maximum T20 he can play 17 games...

bollocks,no overthrows. answer above then

1751, five sixes, then a single with four overthrows off the last ball of theeach over, then six sixes in final over

surely a bit easier (than bowling northants out) - 100 x 8 = 800, +7 = 807 :) (do you have to use all the numbers? if so: (100x8)+(7x(2+2-3)) and back to the cricket